Question Number 163167 by cortano1 last updated on 04/Jan/22
$$\:\mathrm{6}^{{x}+\mathrm{1}} \:+\mathrm{1}\:=\:\mathrm{8}^{{x}+\mathrm{1}} −\mathrm{27}^{{x}} \: \\ $$$$\:{x}=? \\ $$
Answered by MJS_new last updated on 05/Jan/22
$${x}=\mathrm{0}\vee{x}=\mathrm{1} \\ $$