Question Number 32236 by momo last updated on 22/Mar/18
Answered by ajfour last updated on 22/Mar/18
$${a}=\frac{{Mg}\mathrm{sin}\:\theta_{{S}} }{\frac{\mathrm{7}}{\mathrm{5}}{MR}^{\mathrm{2}} }\:=\:\frac{{mg}\mathrm{sin}\:\theta_{{C}} }{\frac{\mathrm{3}}{\mathrm{2}}{mR}^{\mathrm{2}} } \\ $$$$\Rightarrow\:\:\:\frac{\mathrm{sin}\:\theta_{{C}} }{\mathrm{sin}\:\theta_{{S}} }\:\:=\:\:\frac{\mathrm{15}}{\mathrm{14}}\:\:. \\ $$