Question Number 134116 by ClarkeMelodyWenkeh last updated on 27/Feb/21
Answered by EDWIN88 last updated on 27/Feb/21
$$\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{x}+\mathrm{3}\right)−\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{x}\right)=\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{8}\right) \\ $$$$\:\Leftrightarrow\:\frac{\mathrm{x}+\mathrm{3}}{\mathrm{x}}\:=\:\mathrm{8}\:,\:\mathrm{3}\:=\:\mathrm{7x}\:,\:\mathrm{x}\:=\:\frac{\mathrm{3}}{\mathrm{7}} \\ $$