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Question-98190




Question Number 98190 by behi83417@gmail.com last updated on 12/Jun/20
Answered by mr W last updated on 12/Jun/20
Commented by mr W last updated on 12/Jun/20
A_(shaded) =((πr^2 )/4)−(r^2 /2)=(((π−2)r^2 )/4)=((49(π−2))/4)
$${A}_{{shaded}} =\frac{\pi{r}^{\mathrm{2}} }{\mathrm{4}}−\frac{{r}^{\mathrm{2}} }{\mathrm{2}}=\frac{\left(\pi−\mathrm{2}\right){r}^{\mathrm{2}} }{\mathrm{4}}=\frac{\mathrm{49}\left(\pi−\mathrm{2}\right)}{\mathrm{4}} \\ $$
Commented by behi83417@gmail.com last updated on 12/Jun/20
thanks a lot dear mr W!
$$\mathrm{thanks}\:\mathrm{a}\:\mathrm{lot}\:\mathrm{dear}\:\mathrm{mr}\:\mathrm{W}! \\ $$

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