Question Number 32794 by Rio Mike last updated on 02/Apr/18
$${given}\:{that}\:{the}\:{point}\:\left(\bar {{t}},\mathrm{0}\right)\:{lies}\:{on}\:{the} \\ $$$${curve}\:{y}=\mathrm{2}{x}^{\mathrm{2}} −{x}.\:{find}\:{the}\:{value}\:{of}\:{t}. \\ $$
Answered by Joel578 last updated on 02/Apr/18
$${y}\:=\:\mathrm{2}{x}^{\mathrm{2}} \:−\:{x} \\ $$$$\mathrm{0}\:=\:\mathrm{2}{t}^{\mathrm{2}} \:−\:{t} \\ $$$${t}\left(\mathrm{2}{t}\:−\:\mathrm{1}\right)\:=\:\mathrm{0} \\ $$$${t}\:=\:\mathrm{0}\:\:\:\:\vee\:\:\:\:{t}\:=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$