Question Number 164068 by HongKing last updated on 13/Jan/22
Answered by Rasheed.Sindhi last updated on 13/Jan/22
$$\mathrm{sin}\left(\mathrm{x}\right)=\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{8}}}\:\:=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{x}=\frac{\pi}{\mathrm{6}}+\mathrm{2}{k}\pi\:;\:\forall{k}\in\mathbb{Z} \\ $$
Commented by mr W last updated on 13/Jan/22
$${as}\:{well}\:{as}\:{x}=\left(\mathrm{2}{k}+\mathrm{1}\right)\pi−\frac{\pi}{\mathrm{6}} \\ $$
Commented by MJS_new last updated on 13/Jan/22
$$\mathrm{I}\:\mathrm{had}\:\mathrm{been}\:\mathrm{waiting}\:\mathrm{for}\:\mathrm{the}\:\mathrm{font}\:\mathrm{to}\:\mathrm{grow}\:\mathrm{a} \\ $$$$\mathrm{little}\:\mathrm{more}… \\ $$
Commented by Ar Brandon last updated on 13/Jan/22
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