Question Number 164445 by mathlove last updated on 17/Jan/22
Commented by mr W last updated on 17/Jan/22
$${i}\:{don}'{t}\:{think}\:{there}\:{is}\:{a}\:{nice}\:{solution}. \\ $$$${one}\:{can}\:{only}\:{approximate}. \\ $$$${x}=\mathrm{2}−{t} \\ $$$${y}=\mathrm{2}+{t} \\ $$$$\left(\mathrm{2}−{t}\right)^{\left(\mathrm{2}−{t}\right)} +\left(\mathrm{2}+{t}\right)^{\left(\mathrm{2}+{t}\right)} =\mathrm{64} \\ $$$${t}\approx\pm\mathrm{1}.\mathrm{393902} \\ $$