Question Number 99023 by joki last updated on 18/Jun/20
Commented by bobhans last updated on 18/Jun/20
$$\mathrm{x}−\mathrm{y}\:=\:\frac{\left(\mathrm{2012}+\mathrm{2014}\right)^{\mathrm{2}} −\mathrm{2}.\mathrm{2012}.\mathrm{2014}}{\mathrm{4027}}−\:\frac{\left(\mathrm{2013}+\mathrm{2017}\right)^{\mathrm{2}} −\mathrm{2}.\mathrm{2013}.\mathrm{2017}}{\mathrm{4041}} \\ $$$$=\:\frac{\mathrm{4026}^{\mathrm{2}} −\mathrm{8104336}}{\mathrm{4027}}−\:\frac{\mathrm{4030}^{\mathrm{2}} −\mathrm{8120442}}{\mathrm{4041}} \\ $$$$=\frac{\mathrm{8104340}}{\mathrm{4027}}−\:\frac{\mathrm{8120458}}{\mathrm{4041}}\:=\:\mathrm{2}.\mathrm{987628976} \\ $$
Commented by joki last updated on 18/Jun/20
$${sir}.{any}\:{way}\:{to}\:{simple}? \\ $$
Commented by MJS last updated on 18/Jun/20
$$\frac{\mathrm{48553574}}{\mathrm{16273107}}=\frac{\mathrm{2}×\mathrm{24276787}}{\mathrm{3}^{\mathrm{2}} ×\mathrm{449}×\mathrm{4027}} \\ $$$$\mathrm{no}\:\mathrm{way}\:\mathrm{to}\:\mathrm{simplify} \\ $$