Question Number 164627 by amin96 last updated on 19/Jan/22
Answered by mahdipoor last updated on 19/Jan/22
$${a}=\mathrm{2018}+\frac{\mathrm{1}}{\mathrm{2019}}=\mathrm{2019}−\frac{\mathrm{2018}}{\mathrm{2019}} \\ $$$${b}=\mathrm{2019}−\frac{\mathrm{1}}{\mathrm{2018}} \\ $$$${c}=\mathrm{2018}+\frac{\mathrm{2019}}{\mathrm{2018}}=\mathrm{2019}+\frac{\mathrm{1}}{\mathrm{2018}} \\ $$$${d}=\mathrm{2020}−\frac{\mathrm{2020}}{\mathrm{2019}}=\mathrm{2019}−\frac{\mathrm{1}}{\mathrm{2019}} \\ $$$$\Rightarrow{a}<{b}<{d}<{c} \\ $$