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Question-164627




Question Number 164627 by amin96 last updated on 19/Jan/22
Answered by mahdipoor last updated on 19/Jan/22
a=2018+(1/(2019))=2019−((2018)/(2019))  b=2019−(1/(2018))  c=2018+((2019)/(2018))=2019+(1/(2018))  d=2020−((2020)/(2019))=2019−(1/(2019))  ⇒a<b<d<c
$${a}=\mathrm{2018}+\frac{\mathrm{1}}{\mathrm{2019}}=\mathrm{2019}−\frac{\mathrm{2018}}{\mathrm{2019}} \\ $$$${b}=\mathrm{2019}−\frac{\mathrm{1}}{\mathrm{2018}} \\ $$$${c}=\mathrm{2018}+\frac{\mathrm{2019}}{\mathrm{2018}}=\mathrm{2019}+\frac{\mathrm{1}}{\mathrm{2018}} \\ $$$${d}=\mathrm{2020}−\frac{\mathrm{2020}}{\mathrm{2019}}=\mathrm{2019}−\frac{\mathrm{1}}{\mathrm{2019}} \\ $$$$\Rightarrow{a}<{b}<{d}<{c} \\ $$

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