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0-1-ln-1-x-ln-x-1-x-dx-




Question Number 164853 by mnjuly1970 last updated on 22/Jan/22
     Ω = ∫_0 ^( 1) (( ln(1+x ).ln(x))/(1−x)) dx
$$ \\ $$$$\:\:\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:{ln}\left(\mathrm{1}+{x}\:\right).{ln}\left({x}\right)}{\mathrm{1}−{x}}\:{dx} \\ $$

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