Question Number 165068 by cortano1 last updated on 25/Jan/22
Commented by bobhans last updated on 25/Jan/22
$$\:\Rightarrow\mathrm{x}^{\mathrm{log}\:_{\mathrm{81}} \left(\mathrm{243}\right)} −\mathrm{2x}\:=\:\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{log}\:_{\mathrm{16}} \left(\mathrm{2}\right)} −\mathrm{8} \\ $$$$\Rightarrow\mathrm{x}^{\frac{\mathrm{5}}{\mathrm{4}}} −\mathrm{2x}\:=\:\left(\mathrm{x}+\mathrm{2}\right)^{\frac{\mathrm{1}}{\mathrm{4}}} −\mathrm{8} \\ $$