Question Number 34202 by Rio Mike last updated on 02/May/18
$$\:\:{find}\:{the}\:{gradient}\:{of}\:{the}\:{curve} \\ $$$$\:\:\:\:{y}=\frac{\mathrm{1}}{{x}}. \\ $$
Answered by MJS last updated on 02/May/18
$$\mathrm{the}\:\mathrm{gradient}\:\mathrm{is}\:{y}' \\ $$$${y}=\frac{\mathrm{1}}{{x}}={x}^{−\mathrm{1}} \\ $$$${y}'=−{x}^{−\mathrm{2}} =−\frac{\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$