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sove-sinx-y-cos-2x-y-xe-x-




Question Number 99819 by mathmax by abdo last updated on 23/Jun/20
sove  sinx y^′  −cos(2x)y =xe^(−x)
$$\mathrm{sove}\:\:\mathrm{sinx}\:\mathrm{y}^{'} \:−\mathrm{cos}\left(\mathrm{2x}\right)\mathrm{y}\:=\mathrm{xe}^{−\mathrm{x}} \\ $$

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