Question Number 99941 by pranavdangi last updated on 24/Jun/20
Answered by Rio Michael last updated on 24/Jun/20
$$\mathrm{The}\:\mathrm{additive}\:\mathrm{inverse}\:\mathrm{of}\:\frac{{a}}{{b}\:}\:\mathrm{is}{x}\:\mathrm{such}\:\mathrm{that}\:\:{x}\:+\:\frac{{a}}{{b}}\:=\:\mathrm{0} \\ $$$$\mathrm{the}\:\mathrm{multiplicative}\:\mathrm{inverse}\:\mathrm{of}\:\frac{{a}}{{b}}\:\mathrm{is}\:{y}\:\mathrm{such}\:\mathrm{that}\:\:\frac{{ya}}{{b}}\:=\:\mathrm{1} \\ $$