Question Number 165599 by mnjuly1970 last updated on 05/Feb/22
Answered by MJS_new last updated on 05/Feb/22
$${f}\left({x}\right)\:\mathrm{is}\:\mathrm{defined}\:\mathrm{for}\:−\mathrm{1}<{x}<\mathrm{1}\:\Rightarrow\:\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}<{f}\left({x}\right)\leqslant\mathrm{1} \\ $$