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Question Number 34645 by JOHNMASANJA last updated on 09/May/18
show that 2tan^(−1) 2 + tan^(−1) 3=  Π +tan^(−1) (1/3)
$${show}\:{that}\:\mathrm{2}{tan}^{−\mathrm{1}} \mathrm{2}\:+\:{tan}^{−\mathrm{1}} \mathrm{3}= \\ $$$$\Pi\:+{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{3}} \\ $$

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