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calculate-0-pi-ln-x-2-2xcos-1-d-x-real-




Question Number 100965 by mathmax by abdo last updated on 29/Jun/20
calculate ∫_0 ^π ln(x^2 −2xcosθ +1)dθ    (x real)
$$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\pi} \mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2xcos}\theta\:+\mathrm{1}\right)\mathrm{d}\theta\:\:\:\:\left(\mathrm{x}\:\mathrm{real}\right) \\ $$

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