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Question-167078




Question Number 167078 by peter frank last updated on 05/Mar/22
Commented by mr W last updated on 07/Mar/22
something is tatally wrong.  if the satellite is just launched into  a small height, say H≈0, you need  infinite enegy: ((mgR)/2)(1+(R/0))→∞.  the lower you launch it the more  energy you need,  this is non−sense.
$${something}\:{is}\:{tatally}\:{wrong}. \\ $$$${if}\:{the}\:{satellite}\:{is}\:{just}\:{launched}\:{into} \\ $$$${a}\:{small}\:{height},\:{say}\:{H}\approx\mathrm{0},\:{you}\:{need} \\ $$$${infinite}\:{enegy}:\:\frac{{mgR}}{\mathrm{2}}\left(\mathrm{1}+\frac{{R}}{\mathrm{0}}\right)\rightarrow\infty. \\ $$$${the}\:{lower}\:{you}\:{launch}\:{it}\:{the}\:{more} \\ $$$${energy}\:{you}\:{need}, \\ $$$${this}\:{is}\:{non}−{sense}. \\ $$
Commented by peter frank last updated on 07/Mar/22
thank you for confirmation
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{for}\:\mathrm{confirmation} \\ $$

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