Menu Close

Assuming-one-of-the-WiFi-towers-of-a-building-is-20km-high-and-has-a-perpendicular-distance-of-15km-to-a-straight-road-Calculate-the-distance-of-the-road-which-receives-a-good-WiFi-signal-if-it-ha




Question Number 167126 by MathsFan last updated on 07/Mar/22
  Assuming one of the WiFi towers of a building is 20km high, and has a perpendicular distance of 15km to a straight road.   Calculate the distance of the road which receives a good WiFi signal if it has a limited range of 45km    (Calculate to four significant figures)
$$ \\ $$Assuming one of the WiFi towers of a building is 20km high, and has a perpendicular distance of 15km to a straight road.
Calculate the distance of the road which receives a good WiFi signal if it has a limited range of 45km

(Calculate to four significant figures)

Commented by mr W last updated on 07/Mar/22
i′d like to know in which country this  20km high WiFi tower stands...
$${i}'{d}\:{like}\:{to}\:{know}\:{in}\:{which}\:{country}\:{this} \\ $$$$\mathrm{20}{km}\:{high}\:{WiFi}\:{tower}\:{stands}… \\ $$
Commented by MathsFan last updated on 07/Mar/22
you′ve made smile Sir (^• ⌣^• )
$${you}'{ve}\:{made}\:{smile}\:{Sir}\:\left(\:^{\bullet} \smile^{\bullet} \right) \\ $$
Commented by mr W last updated on 07/Mar/22
20^2 +15^2 +((x/2))^2 =45^2   x=2(√(45^2 −20^2 −15^2 ))=74.83 km
$$\mathrm{20}^{\mathrm{2}} +\mathrm{15}^{\mathrm{2}} +\left(\frac{{x}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{45}^{\mathrm{2}} \\ $$$${x}=\mathrm{2}\sqrt{\mathrm{45}^{\mathrm{2}} −\mathrm{20}^{\mathrm{2}} −\mathrm{15}^{\mathrm{2}} }=\mathrm{74}.\mathrm{83}\:{km} \\ $$
Commented by TheSupreme last updated on 07/Mar/22
with 45km of range...
$${with}\:\mathrm{45}{km}\:{of}\:{range}… \\ $$
Commented by MathsFan last updated on 07/Mar/22
thank you sir
$${thank}\:{you}\:{sir} \\ $$
Commented by mr W last updated on 07/Mar/22
x=length of road with good reception  of  WiFi signal
$${x}={length}\:{of}\:{road}\:{with}\:{good}\:{reception} \\ $$$${of}\:\:{WiFi}\:{signal} \\ $$
Commented by mr W last updated on 07/Mar/22
Commented by MathsFan last updated on 08/Mar/22
i appreciate sir
$${i}\:{appreciate}\:{sir} \\ $$
Commented by otchereabdullai@gmail.com last updated on 21/Mar/22
most powerful prof!
$$\mathrm{most}\:\mathrm{powerful}\:\mathrm{prof}! \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *