Question Number 167233 by mkam last updated on 10/Mar/22
$$\int\:\frac{{lnx}}{{x}+\mathrm{1}}{dx} \\ $$
Answered by mindispower last updated on 10/Mar/22
$$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)−\int\frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}}{dx} \\ $$$$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)−\int\frac{{ln}\left(\mathrm{1}−\left(−{x}\right)\right)}{−{x}}{d}\left(−{x}\right) \\ $$$$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)+{Li}_{\mathrm{2}} \left(−{x}\right)+{c} \\ $$
Answered by ArnabIndia last updated on 10/Mar/22
Commented by ArnabIndia last updated on 10/Mar/22
i dont know why the picture is showing blurr
Commented by mkam last updated on 11/Mar/22
$${are}\:{you}\:{have}\:{page}\:{on}\:{face}\:{book}\:{app} \\ $$