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Question Number 167380 by MathsFan last updated on 14/Mar/22
 show that   A′ ∪ B′ ∪ C′ =(A∪B∪C)′
$$\:\boldsymbol{{show}}\:\boldsymbol{{that}} \\ $$$$\:\boldsymbol{{A}}'\:\cup\:\boldsymbol{{B}}'\:\cup\:\boldsymbol{{C}}'\:=\left(\boldsymbol{{A}}\cup\boldsymbol{{B}}\cup\boldsymbol{{C}}\right)' \\ $$
Commented by cortano1 last updated on 15/Mar/22
wrong
$$\mathrm{wrong} \\ $$
Commented by Rasheed.Sindhi last updated on 15/Mar/22
 A′ ∪ B′ ∪ C′ =(A∩B∩C)′                           or   A′ ∩ B′ ∩ C′ =(A∪B∪C)′
$$\:\boldsymbol{{A}}'\:\cup\:\boldsymbol{{B}}'\:\cup\:\boldsymbol{{C}}'\:=\left(\boldsymbol{{A}}\cap\boldsymbol{{B}}\cap\boldsymbol{{C}}\right)' \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{or} \\ $$$$\:\boldsymbol{{A}}'\:\cap\:\boldsymbol{{B}}'\:\cap\:\boldsymbol{{C}}'\:=\left(\boldsymbol{{A}}\cup\boldsymbol{{B}}\cup\boldsymbol{{C}}\right)' \\ $$
Commented by MathsFan last updated on 15/Mar/22
 oh i see  thank you sir
$$\:{oh}\:{i}\:{see} \\ $$$${thank}\:{you}\:{sir} \\ $$

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