Question Number 168102 by MathsFan last updated on 03/Apr/22
$${solve}\:{the}\:{differential}\:{equation} \\ $$$${sin}^{\mathrm{3}} {x}\:{y}''+{sinxcosx}\:{y}'+\mathrm{4}{y}=\mathrm{0} \\ $$
solve-the-differential-equation-sin-3-x-y-sinxcosx-y-4y-0-