Question Number 168402 by BagusSetyoWibowo last updated on 10/Apr/22
$$\mathrm{2}{x}^{\mathrm{3}} +\mathrm{9}{x}^{\mathrm{2}} +\mathrm{13}{x}+\mathrm{6}=\mathrm{0} \\ $$$${Solve}\:{the}\:{x},\:\left({Use}\:{Cubic}\:{Formula}!\right) \\ $$$${x}_{\mathrm{1}} =? \\ $$$${x}_{\mathrm{2}} =? \\ $$$${x}_{\mathrm{3}} =? \\ $$
Commented by cortano1 last updated on 10/Apr/22
$${x}_{\mathrm{1}} =−\frac{\mathrm{3}}{\mathrm{2}} \\ $$$${x}_{\mathrm{2}} =−\mathrm{2} \\ $$$${x}_{\mathrm{3}} =−\mathrm{1} \\ $$