Question Number 103239 by 9027201563 last updated on 13/Jul/20
Answered by OlafThorendsen last updated on 13/Jul/20
$$\mathrm{100}\:\mathrm{N}\:×\mathrm{cos45}°+\mathrm{60}\:\mathrm{N}\:=\:\mathrm{10}\:\mathrm{kg}\:×{a} \\ $$$${a}\:=\:\mathrm{10cos45}°+\mathrm{6}\:\approx\:\mathrm{13},\mathrm{1}\:\mathrm{m}.\mathrm{s}^{−\mathrm{2}} \\ $$$$\Rightarrow\:\boldsymbol{\mathrm{B}} \\ $$
Commented by 9027201563 last updated on 13/Jul/20
$$\mathrm{thanks} \\ $$