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How-can-we-solve-second-order-differential-equations-with-non-constant-coefficients-Any-idea-please-




Question Number 103266 by Ar Brandon last updated on 13/Jul/20
How can we solve second-order differential equations with  non-constant coefficients ? Any idea, please ?
$$\mathrm{How}\:\mathrm{can}\:\mathrm{we}\:\mathrm{solve}\:\mathrm{second}-\mathrm{order}\:\mathrm{differential}\:\mathrm{equations}\:\mathrm{with} \\ $$$$\mathrm{non}-\mathrm{constant}\:\mathrm{coefficients}\:?\:\mathrm{Any}\:\mathrm{idea},\:\mathrm{please}\:? \\ $$$$ \\ $$
Commented by Ar Brandon last updated on 13/Jul/20
Example;  y′′(x)+((2x)/(1+x^2 ))y′(x)+(2−x^2 )y(x)=0
$$\mathrm{Example}; \\ $$$$\mathrm{y}''\left(\mathrm{x}\right)+\frac{\mathrm{2x}}{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\mathrm{y}'\left(\mathrm{x}\right)+\left(\mathrm{2}−\mathrm{x}^{\mathrm{2}} \right)\mathrm{y}\left(\mathrm{x}\right)=\mathrm{0} \\ $$

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