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Re-2-e-i-t-




Question Number 168856 by MWSuSon last updated on 19/Apr/22
Re(2+e^(iαt) )?
$$\mathrm{Re}\left(\mathrm{2}+\mathrm{e}^{\mathrm{i}\alpha\mathrm{t}} \right)? \\ $$
Answered by MJS_new last updated on 19/Apr/22
2+e^(iαt) =2+cos αt +i sin αt  easy, ain′t it?
$$\mathrm{2}+\mathrm{e}^{\mathrm{i}\alpha{t}} =\mathrm{2}+\mathrm{cos}\:\alpha{t}\:+\mathrm{i}\:\mathrm{sin}\:\alpha{t} \\ $$$$\mathrm{easy},\:\mathrm{ain}'\mathrm{t}\:\mathrm{it}? \\ $$
Commented by mokys last updated on 20/Apr/22
2 + cosαt
$$\mathrm{2}\:+\:{cos}\alpha{t} \\ $$

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