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Question-168942




Question Number 168942 by Tawa11 last updated on 21/Apr/22
Commented by mr W last updated on 21/Apr/22
(m_g +m_b +m_s )v_1 =(m_g +m_b )v_(2b) +m_s v_(2s)   v_(2b) =(((m_g +m_b +m_s )v_1 −m_s v_(2s) )/(m_g +m_b ))        =(((50+0.5)×5−0.5×15)/(50))=4.9 m/s
$$\left({m}_{{g}} +{m}_{{b}} +{m}_{{s}} \right){v}_{\mathrm{1}} =\left({m}_{{g}} +{m}_{{b}} \right){v}_{\mathrm{2}{b}} +{m}_{{s}} {v}_{\mathrm{2}{s}} \\ $$$${v}_{\mathrm{2}{b}} =\frac{\left({m}_{{g}} +{m}_{{b}} +{m}_{{s}} \right){v}_{\mathrm{1}} −{m}_{{s}} {v}_{\mathrm{2}{s}} }{{m}_{{g}} +{m}_{{b}} }\: \\ $$$$\:\:\:\:\:=\frac{\left(\mathrm{50}+\mathrm{0}.\mathrm{5}\right)×\mathrm{5}−\mathrm{0}.\mathrm{5}×\mathrm{15}}{\mathrm{50}}=\mathrm{4}.\mathrm{9}\:{m}/{s} \\ $$
Commented by Tawa11 last updated on 21/Apr/22
Wow, God bless you sir.
$$\mathrm{Wow},\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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