Question Number 103585 by aurpeyz last updated on 15/Jul/20
Answered by Worm_Tail last updated on 16/Jul/20
$${CW}={ACW} \\ $$$$\:\:\:\left(\mathrm{430}×\mathrm{9}.\mathrm{8}×\mathrm{2}.\mathrm{5}\right)+\left(\mathrm{85}×\mathrm{9}.\mathrm{8}×\frac{\sqrt{\mathrm{1}.\mathrm{67}^{\mathrm{2}} +\mathrm{2}.\mathrm{5}^{\mathrm{2}} }}{\mathrm{2}}{sin}\left({tan}^{−\mathrm{1}} \frac{\mathrm{2}.\mathrm{5}}{\mathrm{1}.\mathrm{67}}\right)\right)={T}\left(\mathrm{1}.\mathrm{67}\right) \\ $$$$\:\:\:\left(\mathrm{10535}\right)+\left(\mathrm{1041}.\mathrm{25}\right)={T}\left(\mathrm{1}.\mathrm{67}\right) \\ $$$$\:\:\:\mathrm{11576}.\mathrm{25}={T}\left(\mathrm{1}.\mathrm{67}\right) \\ $$$${T}=\frac{\mathrm{11576}.\mathrm{25}}{\mathrm{1}.\mathrm{67}}=\mathrm{6931}.\mathrm{886288}{N} \\ $$