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R-e-2ipiax-1-x-2-2-dx-pie-2pia-1-2-pia-a-gt-0-




Question Number 103820 by ~blr237~ last updated on 17/Jul/20
   ∫_R ^  (e^(−2iπax) /((1+x^2 )^2 ))dx = πe^(−2πa) ((1/2)+πa)         a>0
$$\:\:\:\int_{\mathbb{R}} ^{} \:\frac{{e}^{−\mathrm{2}{i}\pi{ax}} }{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx}\:=\:\pi{e}^{−\mathrm{2}\pi{a}} \left(\frac{\mathrm{1}}{\mathrm{2}}+\pi{a}\right)\:\:\:\:\:\:\:\:\:{a}>\mathrm{0} \\ $$
Answered by mathmax by abdo last updated on 18/Jul/20
my answer is correct but i delet the post...!
$$\mathrm{my}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{correct}\:\mathrm{but}\:\mathrm{i}\:\mathrm{delet}\:\mathrm{the}\:\mathrm{post}…! \\ $$

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