Question Number 169874 by sciencestudent last updated on 11/May/22
$$\underset{{d}\mid\mathrm{6}} {\sum}{d}=? \\ $$
Answered by alephzero last updated on 11/May/22
![Σ_(d∣6) d = [1∣6 ∧ 2∣6 ∧ 3∣6 ∧ 6∣6] = 1+2+3+6 = 12](https://www.tinkutara.com/question/Q169877.png)
$$\underset{{d}\mid\mathrm{6}} {\sum}{d}\:= \\ $$$$\left[\mathrm{1}\mid\mathrm{6}\:\wedge\:\mathrm{2}\mid\mathrm{6}\:\wedge\:\mathrm{3}\mid\mathrm{6}\:\wedge\:\mathrm{6}\mid\mathrm{6}\right] \\ $$$$=\:\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{6}\:=\:\mathrm{12} \\ $$
Commented by sciencestudent last updated on 12/May/22
$${Is}\:{it}\:{not}\:{ans}\:\mathrm{0}? \\ $$