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4-x-x-4-x-




Question Number 170131 by mathlove last updated on 17/May/22
4^(∣x∣) =x^4   x=?
$$\mathrm{4}^{\mid{x}\mid} ={x}^{\mathrm{4}} \\ $$$${x}=? \\ $$
Answered by mr W last updated on 17/May/22
∣x∣=t>0  4^t =t^4   ⇒t=2, 4, −0.7667 (rejected)  ⇒x=±2, ±4
$$\mid{x}\mid={t}>\mathrm{0} \\ $$$$\mathrm{4}^{{t}} ={t}^{\mathrm{4}} \\ $$$$\Rightarrow{t}=\mathrm{2},\:\mathrm{4},\:−\mathrm{0}.\mathrm{7667}\:\left({rejected}\right) \\ $$$$\Rightarrow{x}=\pm\mathrm{2},\:\pm\mathrm{4} \\ $$

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