A-box-contains-5-white-balls-3-black-balls-and-2-red-balls-of-the-same-size-A-ball-is-selected-at-random-from-the-box-and-then-replaced-A-second-ball-is-then-selected-Find-the-probability-of-ob

Question Number 104761 by byaw last updated on 23/Jul/20

$$ \\ $$$$\:\:\mathrm{A}\:\mathrm{box}\:\mathrm{contains}\:\mathrm{5}\:\mathrm{white}\:\mathrm{balls},\:\mathrm{3}\:\mathrm{black} \\ $$$$\mathrm{balls}\:\mathrm{and}\:\mathrm{2}\:\mathrm{red}\:\mathrm{balls}\:\mathrm{of}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{size}.\:\mathrm{A}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{selected}\:\mathrm{at}\:\mathrm{random} \\ $$$$\mathrm{from}\:\mathrm{the}\:\mathrm{box}\:\mathrm{and}\:\mathrm{then}\:\mathrm{replaced}.\:\mathrm{A} \\ $$$$\mathrm{second}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{then}\:\mathrm{selected}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{obtaining}\: \\ $$$$\:\mathrm{one}\:\mathrm{black}\:\mathrm{ball}\:\mathrm{or}\:\mathrm{red}\:\mathrm{ball}\:\mathrm{in}\:\mathrm{any} \\ $$$$\mathrm{order} \\ $$

Commented by mr W last updated on 23/Jul/20

$$\mathrm{2}×\frac{\mathrm{2}}{\mathrm{10}}×\frac{\mathrm{3}}{\mathrm{10}}=\frac{\mathrm{3}}{\mathrm{25}} \\ $$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com