Question Number 170480 by 2407 last updated on 24/May/22
Commented by JDamian last updated on 24/May/22
$$\Sigma\frac{\mathrm{1}}{{k}\left({k}+\mathrm{1}\right)}\:\:{is}\:{a}\:{telescoping}\:{series} \\ $$$$\Sigma\frac{\mathrm{1}}{\mathrm{3}^{{k}+\mathrm{1}} }\:\:\:{is}\:{a}\:{GP} \\ $$$${Then}\:{I}\:{guess}\:{you}\:{can}\:{solve}\:{by}\:\:{yourself} \\ $$
Commented by 2407 last updated on 24/May/22
$${can}\:{please}\:{help}\:{me}\:{solve}.\:{i}\:{have}\:{been}\:{trying}\:{it}\:{no}\:{head}\:{way}\:{out} \\ $$
Commented by JDamian last updated on 25/May/22
Haven't you even searched in wikipedia.org?
https://en.m.wikipedia.org/wiki/Telescoping_series