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Question-170502




Question Number 170502 by cortano1 last updated on 25/May/22
Answered by som(math1967) last updated on 25/May/22
Commented by som(math1967) last updated on 25/May/22
∠DEC=90  ∠ECD=90−15=75  ∠EAC=180−75=105★   ∠ABD=θ=180−105−55=20  ★AECD cyclic
$$\angle{DEC}=\mathrm{90} \\ $$$$\angle{ECD}=\mathrm{90}−\mathrm{15}=\mathrm{75} \\ $$$$\angle{EAC}=\mathrm{180}−\mathrm{75}=\mathrm{105}\bigstar \\ $$$$\:\angle{ABD}=\theta=\mathrm{180}−\mathrm{105}−\mathrm{55}=\mathrm{20} \\ $$$$\bigstar{AECD}\:{cyclic} \\ $$$$ \\ $$
Commented by JDamian last updated on 25/May/22
why do you assume that CD is the diameter of a circle?
Commented by som(math1967) last updated on 25/May/22
I assume from the diagram  if CD is chord (not dia) then   please give any solution
$${I}\:{assume}\:{from}\:{the}\:{diagram} \\ $$$${if}\:{CD}\:{is}\:{chord}\:\left({not}\:{dia}\right)\:{then}\: \\ $$$${please}\:{give}\:{any}\:{solution} \\ $$
Commented by mr W last updated on 25/May/22
there is unique solution only if  CD is diameter.
$${there}\:{is}\:{unique}\:{solution}\:{only}\:{if} \\ $$$${CD}\:{is}\:{diameter}. \\ $$
Answered by mr W last updated on 25/May/22

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