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Question Number 171008 by Mastermind last updated on 06/Jun/22
Find the maximum and minimum  values of h(x)=(4/3)x^3 +(9/2)x^2 +5x+8.    Mastermind
$${Find}\:{the}\:{maximum}\:{and}\:{minimum} \\ $$$${values}\:{of}\:{h}\left({x}\right)=\frac{\mathrm{4}}{\mathrm{3}}{x}^{\mathrm{3}} +\frac{\mathrm{9}}{\mathrm{2}}{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{8}. \\ $$$$ \\ $$$${Mastermind} \\ $$
Commented by mr W last updated on 06/Jun/22
lim_(x→−∞) h(x)=−∞  lim_(x→+∞) h(x)=+∞  ⇒h(x) has no minimum or maximum!  it can get any value in (−∞,+∞).
$$\underset{{x}\rightarrow−\infty} {\mathrm{lim}}{h}\left({x}\right)=−\infty \\ $$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}{h}\left({x}\right)=+\infty \\ $$$$\Rightarrow{h}\left({x}\right)\:{has}\:{no}\:{minimum}\:{or}\:{maximum}! \\ $$$${it}\:{can}\:{get}\:{any}\:{value}\:{in}\:\left(−\infty,+\infty\right). \\ $$

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