Question-171255

Question Number 171255 by mnjuly1970 last updated on 11/Jun/22

Commented by mr W last updated on 11/Jun/22

S_(ΔAPB) =((AB×AP cos θ)/2) =((AD×AP cos θ)/4) =((AP^2 )/4) =((8×8)/4)=16

$${S}_{\Delta{APB}} =\frac{{AB}×{AP}\:\mathrm{cos}\:\theta}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{{AD}×{AP}\:\mathrm{cos}\:\theta}{\mathrm{4}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{{AP}^{\mathrm{2}} }{\mathrm{4}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{8}×\mathrm{8}}{\mathrm{4}}=\mathrm{16} \\ $$

Commented by mnjuly1970 last updated on 11/Jun/22