Prove-that-arg-e-z-Im-z-2kpi-k-0-1-2-

Tinku Tara June 4, 2023 None 0 Comments

Question Number 171421 by mokys last updated on 14/Jun/22

Prove that arg(e^z )= Im(z) + 2kπ ,k=0,±1,±2,...(√)

$${Prove}\:{that}\:{arg}\left({e}^{{z}} \right)=\:{Im}\left({z}\right)\:+\:\mathrm{2}{k}\pi\:,{k}=\mathrm{0},\pm\mathrm{1},\pm\mathrm{2},…\sqrt{} \\ $$

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Prove-that-arg-e-z-Im-z-2kpi-k-0-1-2-

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