Question Number 171518 by Mastermind last updated on 16/Jun/22
Commented by JDamian last updated on 16/Jun/22
$${the}\:{same}\:{ever}\:{tricky}\:{puzzles}\:{again}\:{and}\:{again}… \\ $$$${Both}\:{overall}\:{figures}\:{are}\:{not}\:{triangles} \\ $$$${because}\:{the}\:{red}\:{triangle}\:{and}\:{the}\:{dark} \\ $$$${green}\:{one}\:{are}\:\boldsymbol{{not}}\:{similar}. \\ $$$$ \\ $$$${Both}\:{overall}\:{figures}\:{are}\:{actually} \\ $$$${quadrilaterals}. \\ $$$$ \\ $$$${In}\:{math}\:{expressions}\:{you}\:{can}\:{understand} \\ $$$$ \\ $$$$\mathrm{tan}\:\:\theta_{{red}} =\frac{\mathrm{3}}{\mathrm{8}}\:\:\:\:\:\:\:\:\:\mathrm{tan}\:\:\theta_{{dark}\:{green}} =\:\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$ \\ $$$$\frac{\mathrm{3}}{\mathrm{8}}\neq\frac{\mathrm{2}}{\mathrm{5}}\:\:\:\:\Rightarrow\:\:\:\:\theta_{{red}} \:\:\neq\:\:\:\theta_{{dark}\:{green}} \\ $$
Commented by Mastermind last updated on 16/Jun/22
$${Wow} \\ $$$${thanks} \\ $$