Question Number 171921 by Mikenice last updated on 21/Jun/22
$$\frac{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} −\mathrm{9}}}{\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{3}}}=\mathrm{3},\:{find}\:{x} \\ $$
Answered by FelipeLz last updated on 22/Jun/22
$$\frac{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} −\mathrm{9}}}{\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{3}}}\:=\:\mathrm{3} \\ $$$$\frac{{x}^{\mathrm{2}} −\mathrm{9}}{\:{x}+\mathrm{3}}\:=\:\mathrm{3}^{\mathrm{3}} \\ $$$$\frac{\left({x}+\mathrm{3}\right)\left({x}−\mathrm{3}\right)}{\:{x}+\mathrm{3}}\:=\:\mathrm{27} \\ $$$${x}−\mathrm{3}\:=\:\mathrm{27} \\ $$$${x}\:=\:\mathrm{30} \\ $$
Commented by otchereabdullai@gmail.com last updated on 22/Jun/22
$$\mathrm{nice}! \\ $$