Question Number 172088 by Mikenice last updated on 23/Jun/22
Answered by Joepkollie last updated on 23/Jun/22
$$\:\:\:\boldsymbol{{solution}}.. \\ $$$$\:\:\:\boldsymbol{{y}}=\boldsymbol{\mathrm{e}}^{\boldsymbol{{u}}\:} \Rightarrow\Rightarrow\boldsymbol{{y}}'=\boldsymbol{\mathrm{e}}^{\boldsymbol{{u}}} \bullet\boldsymbol{{u}}' \\ $$$$\:\:\:\:\boldsymbol{{y}}'=\mathrm{cos}\boldsymbol{{x}\mathrm{e}}^{\mathrm{sin}\boldsymbol{{x}}} .. \\ $$$$\:\:\boldsymbol{{guru}}\:\boldsymbol{{J}}{o}\boldsymbol{{e}} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$