Question Number 69643 by ahmadshahhimat775@gmail.com last updated on 26/Sep/19
Answered by MJS last updated on 26/Sep/19
$${l}+{w}=\mathrm{8} \\ $$$${l}^{\mathrm{2}} +{w}^{\mathrm{2}} =\mathrm{6}^{\mathrm{2}} \\ $$$$\Rightarrow\:{l}=\mathrm{4}\pm\sqrt{\mathrm{2}}\wedge{w}=\mathrm{4}\mp\sqrt{\mathrm{2}} \\ $$$$\mathrm{perimeter}\:{P}=\mathrm{10}+\mathrm{3}\pi \\ $$