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Question-172611




Question Number 172611 by Mikenice last updated on 29/Jun/22
Answered by MJS_new last updated on 29/Jun/22
I can solve this but I guess ir′s meant to be  ((x^2 +4x)/3)+((84)/(x^2 +4x))=11  t=x^2 +4x  (t/3)+((84)/t)=11  t^2 −33t+252=0  t=12∨t=21  x=−7∨x=−6∨x=2∨x=3
$$\mathrm{I}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{but}\:\mathrm{I}\:\mathrm{guess}\:\mathrm{ir}'\mathrm{s}\:\mathrm{meant}\:\mathrm{to}\:\mathrm{be} \\ $$$$\frac{{x}^{\mathrm{2}} +\mathrm{4}{x}}{\mathrm{3}}+\frac{\mathrm{84}}{{x}^{\mathrm{2}} +\mathrm{4}{x}}=\mathrm{11} \\ $$$${t}={x}^{\mathrm{2}} +\mathrm{4}{x} \\ $$$$\frac{{t}}{\mathrm{3}}+\frac{\mathrm{84}}{{t}}=\mathrm{11} \\ $$$${t}^{\mathrm{2}} −\mathrm{33}{t}+\mathrm{252}=\mathrm{0} \\ $$$${t}=\mathrm{12}\vee{t}=\mathrm{21} \\ $$$${x}=−\mathrm{7}\vee{x}=−\mathrm{6}\vee{x}=\mathrm{2}\vee{x}=\mathrm{3} \\ $$

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