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Question-172631

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Question Number 172631 by Mikenice last updated on 29/Jun/22
Commented by mr W last updated on 29/Jun/22
x!=(x+1)x(x−1) x(x−1)(x−2)!=(x+1)x(x−1) (x−2)!=x+1 let u=x−2 ⇒u!=u+3 ⇒u=3 ⇒x=5 ✓
x!=(x+1)x(x−1)x(x−1)(x−2)!=(x+1)x(x−1)(x−2)!=x+1letu=x−2⇒u!=u+3⇒u=3⇒x=5✓
Commented by Rasheed.Sindhi last updated on 29/Jun/22
∩i⊂∈ sir!
∩i⊂∈sir!
Commented by Tawa11 last updated on 30/Jun/22
Great sir
Greatsir

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