Question Number 107151 by john santu last updated on 09/Aug/20
$$\:\:\:\:\:\:\:\:\:@\mathrm{JS}@ \\ $$$$\left(\mathrm{D}^{\mathrm{2}} +\mathrm{7D}+\mathrm{12}\right)\mathrm{y}\:=\:\mathrm{e}^{\mathrm{x}} \:\mathrm{cos}\:\mathrm{2x}\: \\ $$
JS-D-2-7D-12-y-e-x-cos-2x-