find-dx-1-x-2-1-x-2- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 41846 by maxmathsup by imad last updated on 13/Aug/18 find∫dx1+x2+1−x2 Answered by MJS last updated on 13/Aug/18 ∫dx1+x2+1−x2=12∫1+x2x2dx−12∫1−x2x2dx=[bothintegralsbyparts]=12(arcsinx+arcsinhx)+1−x2−1+x22x+C Commented by math khazana by abdo last updated on 14/Aug/18 thankyousir. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-find-x-1-x-1-x-dx-2-calculate-1-3-x-1-x-1-x-dx-Next Next post: let-f-a-0-pi-2-dx-1-asinx-with-a-R-1-find-a-simple-form-of-f-a-2-calculate-0-pi-2-dx-1-sinx-and-0-pi-2-dx-1-2sinx-3-find-the-value-of-0-pi-2-cosx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.