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Question Number 172989 by SANOGO last updated on 04/Jul/22
calcul: R=+oo Σ_(n=o) ^(+oo) ((2n)/((2n+1)!))x^n
$${calcul}:\:{R}=+{oo}\: \\ $$$$\underset{{n}={o}} {\overset{+{oo}} {\sum}}\frac{\mathrm{2}{n}}{\left(\mathrm{2}{n}+\mathrm{1}\right)!}{x}^{{n}} \\ $$
Answered by mr W last updated on 04/Jul/22
sinh x=Σ_(n=0) ^∞ (x^(2n+1) /((2n+1)!)) ((sinh x)/x)=Σ_(n=0) ^∞ (x^(2n) /((2n+1)!)) (((sinh x)/x))′=Σ_(n=0) ^∞ ((2nx^(2n−1) )/((2n+1)!)) x(((sinh x)/x))′=Σ_(n=0) ^∞ ((2nx^(2n) )/((2n+1)!)) cosh x−((sinh x)/x)=Σ_(n=0) ^∞ ((2nx^(2n) )/((2n+1)!)) replace x with (√x) ⇒cosh (√x)−((sinh (√x))/( (√x)))=Σ_(n=0) ^∞ ((2nx^n )/((2n+1)!))
$$\mathrm{sinh}\:{x}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{x}^{\mathrm{2}{n}+\mathrm{1}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$$$\frac{\mathrm{sinh}\:{x}}{{x}}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{x}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$$$\left(\frac{\mathrm{sinh}\:{x}}{{x}}\right)'=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{nx}^{\mathrm{2}{n}−\mathrm{1}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$$${x}\left(\frac{\mathrm{sinh}\:{x}}{{x}}\right)'=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{nx}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$$$\mathrm{cosh}\:{x}−\frac{\mathrm{sinh}\:{x}}{{x}}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{nx}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$$${replace}\:{x}\:{with}\:\sqrt{{x}} \\ $$$$\Rightarrow\mathrm{cosh}\:\sqrt{{x}}−\frac{\mathrm{sinh}\:\sqrt{{x}}}{\:\sqrt{{x}}}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{nx}^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$
Commented by Tawa11 last updated on 06/Jul/22
Great sir
$$\mathrm{Great}\:\mathrm{sir} \\ $$

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