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Question-108369




Question Number 108369 by mathdave last updated on 16/Aug/20
Answered by Rasheed.Sindhi last updated on 16/Aug/20
Fractions: (x/8),(y/8)    (x/8)+(y/8)=(1/2)⇒x+y=(8/2)=4.....(i)  (x/8)+((5y)/8)=2⇒x+5y=16........(ii)  (ii)−(i):  4y=12⇒y=3⇒x=4−y=4−3=1  Fractions: (1/8),(3/8)
$${Fractions}:\:\frac{{x}}{\mathrm{8}},\frac{{y}}{\mathrm{8}} \\ $$$$ \\ $$$$\frac{{x}}{\mathrm{8}}+\frac{{y}}{\mathrm{8}}=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow{x}+{y}=\frac{\mathrm{8}}{\mathrm{2}}=\mathrm{4}…..\left({i}\right) \\ $$$$\frac{{x}}{\mathrm{8}}+\frac{\mathrm{5}{y}}{\mathrm{8}}=\mathrm{2}\Rightarrow{x}+\mathrm{5}{y}=\mathrm{16}……..\left({ii}\right) \\ $$$$\left({ii}\right)−\left({i}\right): \\ $$$$\mathrm{4}{y}=\mathrm{12}\Rightarrow{y}=\mathrm{3}\Rightarrow{x}=\mathrm{4}−{y}=\mathrm{4}−\mathrm{3}=\mathrm{1} \\ $$$${Fractions}:\:\frac{\mathrm{1}}{\mathrm{8}},\frac{\mathrm{3}}{\mathrm{8}} \\ $$

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