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Question-42878




Question Number 42878 by Raj Singh last updated on 04/Sep/18
Answered by tanmay.chaudhury50@gmail.com last updated on 04/Sep/18
(sp)_1 =4225   (cp)_1 =((100×4225)/(116))  (sp)_2 =4225  (cp)_2 =((100×4225)/(84))  total sp=4225+4225=8450  total cp=4225×100((1/(116))+(1/(84)))=4225×100((1/(4×29))+(1/(4×21)))  total cp=4225×25(((21+29)/(21×29)))=((4225×25×50)/(21×29))  total cp≈8672  overall loss=8672−8450=222  %loss=((222)/(8672))×100≈2.56
$$\left({sp}\right)_{\mathrm{1}} =\mathrm{4225}\:\:\:\left({cp}\right)_{\mathrm{1}} =\frac{\mathrm{100}×\mathrm{4225}}{\mathrm{116}} \\ $$$$\left({sp}\right)_{\mathrm{2}} =\mathrm{4225}\:\:\left({cp}\right)_{\mathrm{2}} =\frac{\mathrm{100}×\mathrm{4225}}{\mathrm{84}} \\ $$$${total}\:{sp}=\mathrm{4225}+\mathrm{4225}=\mathrm{8450} \\ $$$${total}\:{cp}=\mathrm{4225}×\mathrm{100}\left(\frac{\mathrm{1}}{\mathrm{116}}+\frac{\mathrm{1}}{\mathrm{84}}\right)=\mathrm{4225}×\mathrm{100}\left(\frac{\mathrm{1}}{\mathrm{4}×\mathrm{29}}+\frac{\mathrm{1}}{\mathrm{4}×\mathrm{21}}\right) \\ $$$${total}\:{cp}=\mathrm{4225}×\mathrm{25}\left(\frac{\mathrm{21}+\mathrm{29}}{\mathrm{21}×\mathrm{29}}\right)=\frac{\mathrm{4225}×\mathrm{25}×\mathrm{50}}{\mathrm{21}×\mathrm{29}} \\ $$$${total}\:{cp}\approx\mathrm{8672} \\ $$$${overall}\:{loss}=\mathrm{8672}−\mathrm{8450}=\mathrm{222} \\ $$$$\%{loss}=\frac{\mathrm{222}}{\mathrm{8672}}×\mathrm{100}\approx\mathrm{2}.\mathrm{56} \\ $$$$ \\ $$$$ \\ $$

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