Question Number 174404 by Best1 last updated on 31/Jul/22
Answered by alephzero last updated on 31/Jul/22
$${F}\:'\left(\mathrm{2}\right)\:=\:\left({f}\:\circ\:{g}\right)'\left(\mathrm{2}\right)\:=\:{f}'\left({g}\left(\mathrm{2}\right)\right){g}'\left(\mathrm{2}\right)\:= \\ $$$$=\:{f}'\left(\mathrm{8}\right)×\mathrm{4}\:=\:\mathrm{6}×\mathrm{4}\:=\:\mathrm{24} \\ $$