Question Number 43684 by rajesh123456 last updated on 14/Sep/18
$$\mathrm{2}^{\mathrm{30}} /\mathrm{2}^{\mathrm{31}} \\ $$
Commented by Joel578 last updated on 14/Sep/18
$$\frac{\mathrm{2}^{{p}} }{\mathrm{2}^{{q}} }\:=\:\mathrm{2}^{{p}−{q}} \\ $$